What is the domain of f(x)=sqrt((5-x)/(x^2-x-2)) ?

The domain of f(x)=sqrt((5-x)/(x^2-x-2)) is x<-1\lor 2<x<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((5-x)/(x^2-x-2))

domain

f (x) = \frac{5 - x}{x ^{2} - x - 2}

x < - 1 or 2 < x \leq 5

Solution steps

Find non-negative values for radicals:

x < - 1 or 2 < x \leq 5

Find undefined (singularity) points:

x = 2, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or 2 < x \leq 5

\frac{x ^{3} + 2 x ^{2} + x}{x ^{2} - x - 2}

y = \frac{tan ( x )}{sin ( x )} + \frac{c}{sin ( x )}

f (x) = - ∣ x ∣ + ∣ x - 1 ∣

f (x) = x - 4 + 1

f (x) = \frac{5}{e ^{x} - 1}

What is the domain of f(x)=sqrt((5-x)/(x^2-x-2)) ?
The domain of f(x)=sqrt((5-x)/(x^2-x-2)) is x<-1\lor 2<x<= 5