What is the domain of-tan^2(x) ?

The domain of-tan^2(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of-tan^2(x)

domain

- tan^{2} (x)

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Solution steps

Take the denominator(s) of

- tan^{2} (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

- tan^{2} (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

1 - 21 x^{2}

x^{2} + 2 x - 5

\frac{8 x ( x - 5 )}{5 x ^{2} - 34 x - 7}

f (x) = (x^{2} - 3 x + 2)

f (a) = \frac{a ^{2} + 3}{a ^{2} + 3}

What is the domain of-tan^2(x) ?
The domain of-tan^2(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin