定义域 f(x)=sqrt(x^2-4x)+(x^2-3x+2)

解答

定义域

f (x) = x^{2} - 4 x + (x^{2} - 3 x + 2)

x \leq 0 or x \geq 4

间隔符号

(- \infty, 0] \cup [4, \infty)

求解步骤

对于根式找到非负值:

x \leq 0 or x \geq 4

函数定义域

x \leq 0 or x \geq 4

d o main f (x) = \frac{ln ( x - 1 )}{x - 3 + 2 x}

d o main \frac{ln ( x )}{ln ( 3 )}

d o main \frac{1}{1 - ( \frac{1}{x} ) ^{2}}

d o main g (x) = 2 x^{3} - 6 x + 3, - 2 \leq x \leq 2

d o main y = (x - 2)^{5} (2 x + 1)