What is the domain of f(x)=(sqrt(x-3))/(x-7) ?

The domain of f(x)=(sqrt(x-3))/(x-7) is 3 7

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domain of f(x)=(sqrt(x-3))/(x-7)

domain

f (x) = \frac{x - 3}{x - 7}

3 \leq x < 7 or x > 7

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

3 \leq x < 7 or x > 7

2 x^{2} - 5 x + 3

\frac{x}{x ^{2} + 4 x}

f (x) = \frac{( x + 3 )}{( x - 1 )}

\frac{1}{x - 3}

f (x) = ln (9 x^{2} - 64)

What is the domain of f(x)=(sqrt(x-3))/(x-7) ?
The domain of f(x)=(sqrt(x-3))/(x-7) is 3<= x<7\lor x>7