What is the inverse of f(x)=(3x^2-5)/6 ?

The inverse of f(x)=(3x^2-5)/6 is sqrt((6x+5)/3),-sqrt((6x+5)/3)

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inverse of f(x)=(3x^2-5)/6

inverse

f (x) = \frac{3 x ^{2} - 5}{6}

\frac{6 x + 5}{3}, - \frac{6 x + 5}{3}

Solution steps

y = \frac{3 x ^{2} - 5}{6}

Replace

x

with

y

x = \frac{3 y ^{2} - 5}{6}

Solve for

y, x = \frac{3 y ^{2} - 5}{6}

\frac{6 x + 5}{3}, - \frac{6 x + 5}{3}

f (x) = - 2^{2} + 8 x - 11

f (x) = ln (2)

\frac{5}{15}

f (x) = 2 cos (x + 7)

f (x) = (x - 7)^{2} + 10

What is the inverse of f(x)=(3x^2-5)/6 ?
The inverse of f(x)=(3x^2-5)/6 is sqrt((6x+5)/3),-sqrt((6x+5)/3)