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Frequently Asked Questions (FAQ)
What is the inverse of f(x)=(s+1)/(s^2+s-6) ?
- The inverse of f(x)=(s+1)/(s^2+s-6) is (-s+1+sqrt(25s^2+2s+1))/(2s),(-s+1-sqrt(25s^2+2s+1))/(2s)