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Frequently Asked Questions (FAQ)
What is the inverse of (2x^2+20x+68)/(x^2+10x+16) ?
- The inverse of (2x^2+20x+68)/(x^2+10x+16) is (-5x+10+3sqrt(x^2-4))/(x-2),(-5x+10-3sqrt(x^2-4))/(x-2)