逆 (x^2-x+1)/(x^2+1)

解

逆

\frac{x ^{2} - x + 1}{x ^{2} + 1}

\frac{1 + - 4 x ^{2} + 8 x - 3}{2 ( 1 - x )}, \frac{1 - - 4 x ^{2} + 8 x - 3}{2 ( 1 - x )}

解答ステップ

y = \frac{x ^{2} - x + 1}{x ^{2} + 1}

x

を以下で置き換える:

y

x = \frac{y ^{2} - y + 1}{y ^{2} + 1}

y

を解く

x = \frac{y ^{2} - y + 1}{y ^{2} + 1}

\frac{1 + - 4 x ^{2} + 8 x - 3}{2 ( 1 - x )}, \frac{1 - - 4 x ^{2} + 8 x - 3}{2 ( 1 - x )}