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Frequently Asked Questions (FAQ)
What is the inverse of (s^2-10s+21)/((s-3)^2(s+3)) ?
- The inverse of (s^2-10s+21)/((s-3)^2(s+3)) is (1+sqrt(1-4s(-9s+7)))/(2s),(1-sqrt(1-4s(-9s+7)))/(2s)