We've updated our
Privacy Policy effective December 15.
Please read our updated Privacy Policy and tap
Graph
Hide Plot »
Frequently Asked Questions (FAQ)
What is the inverse of h(x)=(-10x+17)^2,x<= 17/10 ?
- The inverse of h(x)=(-10x+17)^2,x<= 17/10 is -(sqrt(x)-17)/(10),-(-sqrt(x)-17)/(10)