What is the inverse of f(x)=((2x+1))/(x-2) ?

The inverse of f(x)=((2x+1))/(x-2) is (1+2x)/(x-2)

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inverse of f(x)=((2x+1))/(x-2)

inverse

f (x) = \frac{( 2 x + 1 )}{x - 2}

\frac{1 + 2 x}{x - 2}

Solution steps

y = \frac{2 x + 1}{x - 2}

Replace

x

with

y

x = \frac{2 y + 1}{y - 2}

Solve for

y, x = \frac{2 y + 1}{y - 2}

\frac{1 + 2 x}{x - 2}

f (x) = \frac{4 x - 3}{7 x + 5}

\frac{2 x - 5}{3 x + 2}

f (x) = e^{x} + \frac{1}{e ^{x}}

y = - \frac{2}{5} x + 3

f (x) = 3 (x + 2)^{3} - 1

What is the inverse of f(x)=((2x+1))/(x-2) ?
The inverse of f(x)=((2x+1))/(x-2) is (1+2x)/(x-2)