What is the inverse of f(x)=-log_{2}(x+1)+3 ?

The inverse of f(x)=-log_{2}(x+1)+3 is 2^{3-x}-1

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inverse of f(x)=-log_{2}(x+1)+3

inverse

f (x) = - lo g_{2} (x + 1) + 3

2^{3 - x} - 1

Solution steps

y = - lo g_{2} (x + 1) + 3

Replace

x

with

y

x = - lo g_{2} (y + 1) + 3

Solve for

y, x = - lo g_{2} (y + 1) + 3

2^{3 - x} - 1

f (x) = \frac{1}{x ^{2} - x - 6}

f (x) = - 5 x - 5 + 5

\frac{( x + 2 )}{x - 1}

+ (- 2) + 4 x + 1

f (x) = 13 - 4 x^{3}

What is the inverse of f(x)=-log_{2}(x+1)+3 ?
The inverse of f(x)=-log_{2}(x+1)+3 is 2^{3-x}-1