What is the derivative of-3cos(2x+pi/3+2) ?

The derivative of-3cos(2x+pi/3+2) is -3(-sin(2x)-sqrt(3)cos(2x))

What is the first derivative of-3cos(2x+pi/3+2) ?

The first derivative of-3cos(2x+pi/3+2) is -3(-sin(2x)-sqrt(3)cos(2x))

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\frac{d}{d x} (- 3 cos (2 x + \frac{π}{3}) + 2)

- 3 (- sin (2 x) - 3 cos (2 x))

Solution steps

\frac{d}{d x} (- 3 cos (2 x + \frac{π}{3}) + 2)

Simplify

- 3 cos (2 x + \frac{π}{3}) + 2 : - 3 (\frac{1}{2} cos (2 x) - \frac{3}{2} sin (2 x)) + 2

= \frac{d}{d x} (- 3 (\frac{1}{2} cos (2 x) - \frac{3}{2} sin (2 x)) + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 (\frac{1}{2} cos (2 x) - \frac{3}{2} sin (2 x))) + \frac{d}{d x} (2)

\frac{d}{d x} (3 (\frac{1}{2} cos (2 x) - \frac{3}{2} sin (2 x))) = 3 (- sin (2 x) - 3 cos (2 x))

\frac{d}{d x} (2) = 0

= - 3 (- sin (2 x) - 3 cos (2 x)) + 0

Simplify

= - 3 (- sin (2 x) - 3 cos (2 x))

y = (lo g_{5} (x)) + 2

f (n) = lo g_{2} (lo g_{2} (n))

y = (\frac{x ^{2} + 1}{x ^{2} - 1})^{3}

h (x) = - 16 x^{2} + 72 x + 40

f (x) = e^{2 x + 3} - e^{4 x + 3} + 2 e^{3}

What is the derivative of-3cos(2x+pi/3+2) ?
The derivative of-3cos(2x+pi/3+2) is -3(-sin(2x)-sqrt(3)cos(2x))
What is the first derivative of-3cos(2x+pi/3+2) ?
The first derivative of-3cos(2x+pi/3+2) is -3(-sin(2x)-sqrt(3)cos(2x))