What is area y=2x+2,y=x^2+2,x=-1,x=3 ?

The answer to area y=2x+2,y=x^2+2,x=-1,x=3 is 4

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area y=2x+2,y=x^2+2,x=-1,x=3

area

y = 2 x + 2, y = x^{2} + 2, x = - 1, x = 3

4

Solution steps

Apply the area formula:

\int_{- 1}^{3} 2 x + 2 - (x^{2} + 2) d x

Solve

\int_{- 1}^{3} 2 x + 2 - (x^{2} + 2) d x : 4

The area is:

= 4

x \to - π lim (\frac{sin ( x )}{x})

\int 2 t + 1 d t

d er i v a t i v e y = ln (1 - x^{2})

\int_{0}^{y} 0.5 d x

d er i v a t i v e f (x) = cos (sin (tan (π x)))

What is area y=2x+2,y=x^2+2,x=-1,x=3 ?
The answer to area y=2x+2,y=x^2+2,x=-1,x=3 is 4