What is the derivative of f(x)=x^2+3x-7 ?

The derivative of f(x)=x^2+3x-7 is 2x+3

What is the first derivative of f(x)=x^2+3x-7 ?

The first derivative of f(x)=x^2+3x-7 is 2x+3

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derivative of

f (x) = x^{2} + 3 x - 7

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (7) = 0

= 2 x + 3 - 0

Simplify

= 2 x + 3

\frac{\partial}{\partial s} (- 3 s^{2} + t^{2})

y^{^{'}} = y + 3

\int \frac{1}{x ^{2} + 6 x} d x

\frac{d}{d x} (e^{1 x})

d er i v a t i v e f (x) = 7 x - 2 x

What is the derivative of f(x)=x^2+3x-7 ?
The derivative of f(x)=x^2+3x-7 is 2x+3
What is the first derivative of f(x)=x^2+3x-7 ?
The first derivative of f(x)=x^2+3x-7 is 2x+3