integral from 0 to pi of sin^2(3x)

Lösung

\int_{0}^{π} sin^{2} (3 x) d x

\frac{π}{2}

Dezimale

1.57079 \dots

Schritte zur Lösung

\int_{0}^{π} sin^{2} (3 x) d x

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= \int_{0}^{π} \frac{1}{2} (1 - cos (6 x)) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{π} 1 - cos (6 x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{π} 1 d x - \int_{0}^{π} cos (6 x) d x)

\int_{0}^{π} 1 d x = π

\int_{0}^{π} cos (6 x) d x = 0

= \frac{1}{2} (π - 0)

Vereinfache

\frac{1}{2} (π - 0) : \frac{π}{2}

= \frac{π}{2}

y^{^{''}} + 121 y = sec (11 x), y (0) = - 5, y^{^{'}} (0) = 6

\frac{\partial}{\partial y} (3 x (y - 1)^{\frac{1}{3}})

\frac{d}{d x} (- \frac{9 x}{y})

\frac{\partial}{\partial y} (x^{2} + y e^{x})

\frac{\partial}{\partial y} (ln (x - 6 y))