tangent f(x)=x^3-2/(x^2)+2,(1,3)

Lösung

tangente von

f (x) = x^{3} - \frac{2}{x ^{2}} + 2, (1, 3)

y = 15.59616 \dots x - 12.59616 \dots or y = 1.87099 \dots x + 1.12900 \dots

Schritte zur Lösung

Steigung der Tangente an

(1, 3) : m = \frac{x ^{5} - 2 - x ^{2}}{x ^{2} ( x - 1 )}

Finde die Steigung von

f (x) = x^{3} - \frac{2}{x ^{2}} + 2 : m = 3 x^{2} + \frac{4}{x ^{3}}

Löse

3 x^{2} + \frac{4}{x ^{3}} = \frac{x ^{5} - 2 - x ^{2}}{x ^{2} ( x - 1 )} : x \approx 0.65378 \dots, x \approx - 1.18972 \dots

Finde die Tangente an

x = 0.65378 \dots : y = 15.59616 \dots x - 12.59616 \dots

Finde die Tangente an

x = - 1.18972 \dots : y = 1.87099 \dots x + 1.12900 \dots

y = 15.59616 \dots x - 12.59616 \dots or y = 1.87099 \dots x + 1.12900 \dots

\frac{\partial}{\partial x} (x^{1})

\frac{\partial}{\partial x} (\frac{2 x + y}{z})

\int_{0}^{\frac{3 π}{2}} cos^{3} (29 x) d x

\frac{d}{d x} (\frac{x ^{3} + 3 x}{x ^{2} - 4 x + 3})

x \to \infty lim (- 2 e^{x})