derivative of x/2+3/2+4/(x+1)

Lösung

\frac{d}{d x} (\frac{x}{2} + \frac{3}{2} + \frac{4}{x + 1})

- \frac{4}{( x + 1 ) ^{2}} + \frac{1}{2}

Schritte zur Lösung

\frac{d}{d x} (\frac{x}{2} + \frac{3}{2} + \frac{4}{x + 1})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{2}) + \frac{d}{d x} (\frac{3}{2}) + \frac{d}{d x} (\frac{4}{x + 1})

\frac{d}{d x} (\frac{x}{2}) = \frac{1}{2}

\frac{d}{d x} (\frac{3}{2}) = 0

\frac{d}{d x} (\frac{4}{x + 1}) = - \frac{4}{( x + 1 ) ^{2}}

= \frac{1}{2} + 0 - \frac{4}{( x + 1 ) ^{2}}

Vereinfache

= - \frac{4}{( x + 1 ) ^{2}} + \frac{1}{2}

x (x - 4) y^{^{'}} + y = 0

d er i v a t i v e x ln (2 x)

\int cos^{4} (x) d x

\frac{d}{d t} (a_{2} t cos (2 t) + a_{2} t sin (2 t))

\int 1