What is the limit as x approaches 8 of \sqrt[3]{x} ?

The limit as x approaches 8 of \sqrt[3]{x} is 2

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limit as x approaches 8 of \sqrt[3]{x}

x \to 8 lim (3 x)

2

Solution steps

x \to 8 lim (3 x)

Plug in the value

x = 8

= 38

Simplify

38 : 2

= 2

t an g e n t f (x) = \frac{4}{5 x + 1}, at x = - 1

(ln (sin (x)))^{^{'}}

\int_{3}^{6} (3 x - x)^{2} d x

\int (x^{20} - 5 x^{4})^{3} (x^{19} - x^{3}) d x

t an g e n t f (x) = \frac{6}{x}, at x = 4

What is the limit as x approaches 8 of \sqrt[3]{x} ?
The limit as x approaches 8 of \sqrt[3]{x} is 2