derivative of (8x-1/(6x+7))

Lösung

\frac{d}{d x} (\frac{8 x - 1}{6 x + 7})

\frac{62}{( 6 x + 7 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{8 x - 1}{6 x + 7})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 8 x - 1 ) ( 6 x + 7 ) - \frac{d}{d x} ( 6 x + 7 ) ( 8 x - 1 )}{( 6 x + 7 ) ^{2}}

\frac{d}{d x} (8 x - 1) = 8

\frac{d}{d x} (6 x + 7) = 6

= \frac{8 ( 6 x + 7 ) - 6 ( 8 x - 1 )}{( 6 x + 7 ) ^{2}}

Multipliziere aus

8 (6 x + 7) - 6 (8 x - 1) : 62

= \frac{62}{( 6 x + 7 ) ^{2}}

\int - ln (x) - \frac{ln ( x )}{4} d x

\int_{- 2}^{4} t^{2} - 2 t - 3 d t

f^{^{'}} (x) = 2 x^{2} + 3 x - 2

\frac{\partial}{\partial x} (x^{4} y - x^{2} y^{3})

d er i v a t i v e y = 3 x^{2} + \frac{4 x}{3} - 2