What is the derivative of 3^x-2 ?

The derivative of 3^x-2 is ln(3)*3^x

What is the first derivative of 3^x-2 ?

The first derivative of 3^x-2 is ln(3)*3^x

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\frac{d}{d x} (3^{x} - 2)

ln (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (3^{x} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3^{x}) - \frac{d}{d x} (2)

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

\frac{d}{d x} (2) = 0

= 3^{x} ln (3) - 0

Simplify

= ln (3) \cdot 3^{x}

\frac{d}{d x} (e^{x^{2}} y)

\int \frac{1}{3} x^{2} d x

x \to 0 lim (x^{3} + x)

\int \frac{2}{( x ^{2} + 1 ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (\frac{1 - 3 x}{2 x + 1})

What is the derivative of 3^x-2 ?
The derivative of 3^x-2 is ln(3)*3^x
What is the first derivative of 3^x-2 ?
The first derivative of 3^x-2 is ln(3)*3^x