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Beliebt Rechnen >

(x+y)y^'=2x+2*y-3

Lösung

(x + y) \cdot y^{^{'}} = 2 \cdot x + 2 \cdot y - 3

Lösung

y = W (\frac{1}{3 e ^{- 3 x + 1 - c_{1}}}) + 1 - x

Schritte zur Lösung

(x + y) \cdot y^{'} (x) = 2 \cdot x + 2 \cdot y - 3

Solve using substitution:

y = W (\frac{1}{3 e ^{- 3 x + 1 - c_{1}}}) + 1 - x

y = W (\frac{1}{3 e ^{- 3 x + 1 - c_{1}}}) + 1 - x

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