What is the derivative of (x^2+4x-5^4) ?

The derivative of (x^2+4x-5^4) is 4(x^2+4x-5)^3(2x+4)

What is the first derivative of (x^2+4x-5^4) ?

The first derivative of (x^2+4x-5^4) is 4(x^2+4x-5)^3(2x+4)

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\frac{d}{d x} ((x^{2} + 4 x - 5)^{4})

4 (x^{2} + 4 x - 5)^{3} (2 x + 4)

Solution steps

\frac{d}{d x} ((x^{2} + 4 x - 5)^{4})

Apply the chain rule:

4 (x^{2} + 4 x - 5)^{3} \frac{d}{d x} (x^{2} + 4 x - 5)

= 4 (x^{2} + 4 x - 5)^{3} \frac{d}{d x} (x^{2} + 4 x - 5)

\frac{d}{d x} (x^{2} + 4 x - 5) = 2 x + 4

= 4 (x^{2} + 4 x - 5)^{3} (2 x + 4)

\int x^{2} cos (\frac{x}{2}) d x

d er i v a t i v e e^{t}

\int e^{t^{2}} t^{3} d t

\frac{d ^{2}}{d x ^{2}} (4 x^{3} - 5 x^{4})

im pl i c i t sin (x y) = cos (x + y)

What is the derivative of (x^2+4x-5^4) ?
The derivative of (x^2+4x-5^4) is 4(x^2+4x-5)^3(2x+4)
What is the first derivative of (x^2+4x-5^4) ?
The first derivative of (x^2+4x-5^4) is 4(x^2+4x-5)^3(2x+4)