What is the tangent of f(x)=2sin^2(pix),\at x= 3/4 ?

The tangent of f(x)=2sin^2(pix),\at x= 3/4 is y=-2pix+1+(3pi)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=2sin^2(pix),\at x= 3/4

tangent of

f (x) = 2 sin^{2} (π x), at x = \frac{3}{4}

y = - 2 π x + 1 + \frac{3 π}{2}

Solution steps

Find the tangent point:

(\frac{3}{4}, 1)

Find the slope of

f (x) = 2 sin^{2} (π x) : \frac{df ( x )}{d x} = 4 π sin (π x) cos (π x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2 π

Find the line with slope m=

- 2 π

and passing through

(\frac{3}{4}, 1) : y = - 2 π x + 1 + \frac{3 π}{2}

y = - 2 π x + 1 + \frac{3 π}{2}

\int 4 3 x - cos (x) d x

\frac{d}{d t} (sin (a t))

p a r t ia l f r a c t i o n \frac{x ^{2}}{x + 4}

d er i v a t i v e \frac{ln ( x ) + 2}{x ^{2}}

\int \frac{1}{- t ^{2} + 2 t + 3} d t

What is the tangent of f(x)=2sin^2(pix),\at x= 3/4 ?
The tangent of f(x)=2sin^2(pix),\at x= 3/4 is y=-2pix+1+(3pi)/2