What is the integral of 1/(x^{3/4)} ?

The integral of 1/(x^{3/4)} is 4x^{1/4}+C

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integral of 1/(x^{3/4)}

\int \frac{1}{x ^{\frac{3}{4}}} d x

4 x^{\frac{1}{4}} + C

Solution steps

\int \frac{1}{x ^{\frac{3}{4}}} d x

Apply the Power Rule

= 4 x^{\frac{1}{4}}

Add a constant to the solution

= 4 x^{\frac{1}{4}} + C

x \to 0 lim (2^{\frac{1}{2}})

\int_{5}^{\infty} e^{- \frac{x}{4}} d x

\int \frac{3}{( x + 1 ) ^{2}} d x

\int 1 + x^{3} d x

t an g e n t f (x) = \frac{x ^{2}}{x - 3}