What is the first derivative of 3x-6 ?

The first derivative of 3x-6 is 3

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derivative of 3x-6

\frac{d}{d x} (3 x - 6)

3

Solution steps

\frac{d}{d x} (3 x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (6)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (6) = 0

= 3 - 0

Simplify

= 3

\int \frac{1}{x + 2 + x} d x

\frac{d}{d t} (a cos (4 t) + b sin (4 t))

(x e^{x})^{^{'}}

\frac{d y}{d x} = y^{3} x e^{x^{2}}, y (0) = 1

d er i v a t i v e 5 2 x