f^'(x)=6sqrt(x)+12^{3/4}

Lösung

f^{^{'}} (x) = 6 x + 1 2^{\frac{3}{4}}

f (x) = 4 x^{\frac{3}{2}} + 1 2^{\frac{3}{4}} x + c_{1}

Schritte zur Lösung

f^{'} (x) = 6 x + 1 2^{\frac{3}{4}}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int 6 x + 1 2^{\frac{3}{4}} d x

\int 6 x + 1 2^{\frac{3}{4}} d x = 4 x^{\frac{3}{2}} + 1 2^{\frac{3}{4}} x + c_{1}

f (x) = 4 x^{\frac{3}{2}} + 1 2^{\frac{3}{4}} x + c_{1}

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