(\partial)/(\partial y)(x+cos(xyz)-1)

Lösung

\frac{\partial}{\partial y} (x + cos (x yz) - 1)

- x z sin (x yz)

Schritte zur Lösung

\frac{\partial}{\partial y} (x + cos (x yz) - 1)

Behandle

x, z

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (cos (x yz)) - \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (cos (x yz)) = - sin (x yz) x z

\frac{\partial}{\partial y} (1) = 0

= 0 - sin (x yz) x z - 0

Vereinfache

= - x z sin (x yz)

l c m 2 x, x^{2 - 3}

\frac{d}{d x} (sin (x) + \frac{2}{9} cot (x))

d er i v a t i v e ln (14 x)

\frac{d}{d x} (\frac{108}{x})

d er i v a t i v e f (x) = (2 t - 1) (6 t - 6)^{- 1}