(1xy^2+4y)dx+(1x^2y+4x)dy=0

Lösung

(1 x y^{2} + 4 y) d x + (1 x^{2} y + 4 x) d y = 0

y = \frac{c _{1}}{x}

Schritte zur Lösung

(1 x y^{2} + 4 y) d x + (1 x^{2} y + 4 x) d y = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

d er i v a t i v e y = x^{2} - 6 x + 9

\frac{d}{d x} (a x^{2} + b x)

d er i v a t i v e f (x) = \frac{cos ( x )}{x ^{4}}

x \to - 2 - lim (\frac{x - 3}{x ^{2} - 4})

\frac{d}{d x} (x^{2} arctan (5 x) + ln (1 + 4 x^{2}))