(dy)/(dx)=4y+3e^{8x}(x+1),y(0)=0

解答

\frac{d y}{d x} = 4 y + 3 e^{8 x} (x + 1), y (0) = 0

y = 3 e^{8 x} (\frac{x}{4} + \frac{3}{16}) - \frac{9}{16} e^{4 x}

求解步骤

\frac{d y}{d x} = 4 y + 3 e^{8 x} (x + 1)

求解线性方程:

y = 3 e^{8 x} (\frac{x}{4} + \frac{3}{16}) - \frac{9}{16} e^{4 x}

y = 3 e^{8 x} (\frac{x}{4} + \frac{3}{16}) - \frac{9}{16} e^{4 x}

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