derivative 569+t(37t^{0.6}-108)

解答

导数

569 + t (37 t^{0.6} - 108)

59.2 t^{0.6} - 108

求解步骤

\frac{d}{d t} (569 + t (37 t^{0.6} - 108))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (569) + \frac{d}{d t} (t (37 t^{0.6} - 108))

\frac{d}{d t} (569) = 0

\frac{d}{d t} (t (37 t^{0.6} - 108)) = 59.2 t^{0.6} - 108

= 0 + 59.2 t^{0.6} - 108

化简

= 59.2 t^{0.6} - 108

\frac{d r}{d θ} = \frac{r ^{2} + 10 r θ}{5 θ ^{2}}

y^{^{''}} - 18 y^{^{'}} + 77 y = 0

\int x^{- 2} ln (x) d x

t an g e n t y = \frac{x + 1}{5 - x}, (7, - 4)

x \to - 2 lim (\frac{x + 1}{x + 2})