What is the derivative of 2x^2y-x^3 ?

The derivative of 2x^2y-x^3 is 2(2xy+(dy)/(dx)x^2)-3x^2

What is the first derivative of 2x^2y-x^3 ?

The first derivative of 2x^2y-x^3 is 2(2xy+(dy)/(dx)x^2)-3x^2

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\frac{d}{d x} (2 x^{2} y - x^{3})

2 (2 x y + \frac{d y}{d x} x^{2}) - 3 x^{2}

Solution steps

\frac{d}{d x} (2 x^{2} y - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2} y) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (2 x^{2} y) = 2 (2 x y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 2 (2 x y + \frac{d y}{d x} x^{2}) - 3 x^{2}

\frac{\partial}{\partial x} (y^{2} - x^{2})

in v erse l a pl a ce 1 + \frac{1}{s ( s + 2 )}

d er i v a t i v e \frac{1 - 4 x}{2 + x}

\int_{0}^{1} π (2 x)^{2} d x

\int \frac{2 s - 8}{( s ^{2} - 8 s + 25 ) ^{2}} d s

What is the derivative of 2x^2y-x^3 ?
The derivative of 2x^2y-x^3 is 2(2xy+(dy)/(dx)x^2)-3x^2
What is the first derivative of 2x^2y-x^3 ?
The first derivative of 2x^2y-x^3 is 2(2xy+(dy)/(dx)x^2)-3x^2