integral from 0 to 2 of 2x-1

Lösung

\int_{0}^{2} 2 x - 1 d x

2

Schritte zur Lösung

\int_{0}^{2} 2 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x d x - \int_{0}^{2} 1 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= 4 - 2

Vereinfache

= 2

\frac{\partial}{\partial x} (lo g_{y} (x))

\frac{\partial}{\partial x} (x^{3} y + 7 x^{2} y^{2})

f (x) = \frac{x}{( x ^{2} - 1 ) ^{4}}

in v erse l a pl a ce \frac{( 1 )}{s ^{2}}

\frac{\partial}{\partial y} (3 x^{2} + 2 y^{2} - 4 x y + 5)