derivative f(x)=x^3(x-6)^2

Lösung

ableitung von

f (x) = x^{3} (x - 6)^{2}

5 x^{4} - 48 x^{3} + 108 x^{2}

Schritte zur Lösung

\frac{d}{d x} (x^{3} (x - 6)^{2})

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = (x - 6)^{2}

= \frac{d}{d x} (x^{3}) (x - 6)^{2} + \frac{d}{d x} ((x - 6)^{2}) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} ((x - 6)^{2}) = 2 (x - 6)

= 3 x^{2} (x - 6)^{2} + 2 (x - 6) x^{3}

Vereinfache

3 x^{2} (x - 6)^{2} + 2 (x - 6) x^{3} : 5 x^{4} - 48 x^{3} + 108 x^{2}

= 5 x^{4} - 48 x^{3} + 108 x^{2}

f (x) = x - 1 + x + 1

t an g e n t y = (\frac{( x + 2 )}{( x - 2 )})^{2}, at x = 3

\int_{0}^{π} 14 sin^{4} (x) d x

\int \frac{x - 1}{( x + 1 ) ^{3}} d x

x \to 5 lim (x + 3)