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受欢迎的微积分 >

integral from 2 to 5 of x/(x^2+6x+13)

解答

\int_{2}^{5} \frac{x}{x ^{2} + 6 x + 13} d x

解答

\frac{ln ( 68 ) - ln ( 29 ) - 3 ( arctan ( 4 ) - arctan ( \frac{5}{2} ) )}{2}

+1

十进制

0.22281 \dots

求解步骤

\int_{2}^{5} \frac{x}{x ^{2} + 6 x + 13} d x

对

x^{2} + 6 x + 13

配方:

(x + 3)^{2} + 4

= \int_{2}^{5} \frac{x}{( x + 3 ) ^{2} + 4} d x

使用换元积分法

= \int_{5}^{8} \frac{u - 3}{u ^{2} + 4} d u

乘开

\frac{u - 3}{u ^{2} + 4} : \frac{u}{u ^{2} + 4} - \frac{3}{u ^{2} + 4}

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{5}^{8} \frac{u}{u ^{2} + 4} d u - \int_{5}^{8} \frac{3}{u ^{2} + 4} d u

\int_{5}^{8} \frac{u}{u ^{2} + 4} d u = \frac{1}{2} (ln (68) - ln (29))

\int_{5}^{8} \frac{3}{u ^{2} + 4} d u = \frac{3}{2} (arctan (4) - arctan (\frac{5}{2}))

= \frac{1}{2} (ln (68) - ln (29)) - \frac{3}{2} (arctan (4) - arctan (\frac{5}{2}))

化简

\frac{1}{2} (ln (68) - ln (29)) - \frac{3}{2} (arctan (4) - arctan (\frac{5}{2})) : \frac{ln ( 68 ) - ln ( 29 ) - 3 ( arctan ( 4 ) - arctan ( \frac{5}{2} ) )}{2}

= \frac{ln ( 68 ) - ln ( 29 ) - 3 ( arctan ( 4 ) - arctan ( \frac{5}{2} ) )}{2}

作图

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