(dy)/(dx)=((x-3)^2)/(sqrt(x))

Lösung

\frac{d y}{d x} = \frac{( x - 3 ) ^{2}}{x}

y = \frac{2}{5} x^{\frac{5}{2}} - 4 x^{\frac{3}{2}} + 18 x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{( x - 3 ) ^{2}}{x}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{( x - 3 ) ^{2}}{x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{( x - 3 ) ^{2}}{x} d x

\int \frac{( x - 3 ) ^{2}}{x} d x = \frac{2}{5} x^{\frac{5}{2}} - 4 x^{\frac{3}{2}} + 18 x + c_{1}

y = \frac{2}{5} x^{\frac{5}{2}} - 4 x^{\frac{3}{2}} + 18 x + c_{1}

x \cdot \frac{d y}{d x} = \frac{1}{y ^{2}} + y

n = 1 \sum \infty \frac{1}{n ^{2} + 5 n + 6}

\frac{d}{d x} (4 + ln (x))

y^{^{'}} = y (x y^{6} + 1)

\int_{0}^{17} 2 π x (17 x - x^{2}) d x