What is the derivative of ((1-ln(x))/(x^2)) ?

The derivative of ((1-ln(x))/(x^2)) is -(-2ln(x)+3)/(x^3)

What is the first derivative of ((1-ln(x))/(x^2)) ?

The first derivative of ((1-ln(x))/(x^2)) is -(-2ln(x)+3)/(x^3)

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\frac{d}{d x} (\frac{( 1 - ln ( x ) )}{x ^{2}})

- \frac{- 2 ln ( x ) + 3}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{( 1 - ln ( x ) )}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 - ln ( x ) ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( 1 - ln ( x ) )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (1 - ln (x)) = - \frac{1}{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{( - \frac{1}{x} ) x ^{2} - 2 x ( 1 - ln ( x ) )}{( x ^{2} ) ^{2}}

Simplify

\frac{( - \frac{1}{x} ) x ^{2} - 2 x ( 1 - ln ( x ) )}{( x ^{2} ) ^{2}} : - \frac{- 2 ln ( x ) + 3}{x ^{3}}

= - \frac{- 2 ln ( x ) + 3}{x ^{3}}

t an g e n t f (x) = (x - 4) (x^{2} + 8), at x = 1

d er i v a t i v e (8 x + 9) (9 x - 10)

\frac{d}{d x} (e^{- c o s (x)})

d er i v a t i v e \frac{e ^{x}}{5 x + 3}

\int x^{2} sin (x^{3}) d x

What is the derivative of ((1-ln(x))/(x^2)) ?
The derivative of ((1-ln(x))/(x^2)) is -(-2ln(x)+3)/(x^3)
What is the first derivative of ((1-ln(x))/(x^2)) ?
The first derivative of ((1-ln(x))/(x^2)) is -(-2ln(x)+3)/(x^3)