y^'=3x+y,y(0)=7

Lösung

y^{^{'}} = 3 x + y, y (0) = 7

y = - 3 (x + 1) + 10 e^{x}

Schritte zur Lösung

y^{'} (x) = 3 x + y

Solve linear ODE:

y = - 3 (x + 1) + 10 e^{x}

y = - 3 (x + 1) + 10 e^{x}

x \to 0 + lim (x^{2} csc^{2} (x))

x \frac{d y}{d x} = y - \frac{1}{y}

\frac{d}{d x} (\frac{x ^{4} - 5 x ^{3} + x}{x ^{2}})

\frac{d y}{d x} = \frac{e ^{x} + 1}{2 y}

x \to - \infty lim (4 x)