(2x-1)dx+(7y+3)dy=0

Lösung

(2 x - 1) d x + (7 y + 3) d y = 0

y = \frac{- 3 + - 14 ( x ^{2} - x - c _{1} ) + 9}{7}, y = - \frac{- 14 ( x ^{2} - x - c _{1} ) + 9 + 3}{7}

Schritte zur Lösung

(2 x - 1) d x + (7 y + 3) d y = 0

Solve separable ODE:

y = \frac{- 3 + - 14 ( x ^{2} - x - c _{1} ) + 9}{7}, y = - \frac{- 14 ( x ^{2} - x - c _{1} ) + 9 + 3}{7}

y = \frac{- 3 + - 14 ( x ^{2} - x - c _{1} ) + 9}{7}, y = - \frac{- 14 ( x ^{2} - x - c _{1} ) + 9 + 3}{7}

\frac{d}{d x} (2 x cos (2 x) - (x - 2)^{2})

x \to - 2 lim (x^{2} + 4 x + 4)

\frac{d}{d x} (\frac{2 arctan ( x )}{x ^{2} + 1})

d er i v a t i v e f (x) = 2 x^{4} - x^{3} + 6 x^{2}

t an g e n t \frac{x ^{2}}{x - 2}