What is the integral from x to infinity of 2e^{-x-y} ?

The integral from x to infinity of 2e^{-x-y} is 2e^{-2x}

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integral from x to infinity of 2e^{-x-y}

\int_{x}^{\infty} 2 e^{- x - y} d y

2 e^{- 2 x}

Solution steps

\int_{x}^{\infty} 2 e^{- x - y} d y

Compute the indefinite integral:

\int 2 e^{- x - y} d y = - 2 e^{- x - y} + C

Compute the boundaries:

\int_{x}^{\infty} 2 e^{- x - y} d y = 0 - (- 2 e^{- 2 x})

= 0 - (- 2 e^{- 2 x})

Simplify

= 2 e^{- 2 x}

d er i v a t i v e y = 4 x^{2} - 13 x - \frac{9}{x ^{4}}

t an g e n t f (x) = \frac{2}{x}, (- 3, - \frac{2}{3})

\frac{d}{d x} (x - ln (x^{2}))

\int - \frac{3}{x} d x

d er i v a t i v e f (x) = (x - 1) (x^{2} + 2)^{3}

What is the integral from x to infinity of 2e^{-x-y} ?
The integral from x to infinity of 2e^{-x-y} is 2e^{-2x}