derivative of 2x+ln(x)

Lösung

\frac{d}{d x} (2 x + ln (x))

2 + \frac{1}{x}

Schritte zur Lösung

\frac{d}{d x} (2 x + ln (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 + \frac{1}{x}

d er i v a t i v e y = \frac{1}{1 - x}

d er i v a t i v e \frac{x ^{2} + 5}{x}

x \to 4 lim (lo g_{2} (x))

\int \frac{x ^{\frac{1}{2}} + 5}{3 x} d x

\frac{\partial}{\partial x} (x^{2} + 2 x y - y^{2})