y^'=5x+y,y(0)=6

Lösung

y^{^{'}} = 5 x + y, y (0) = 6

y = - 5 (x + 1) + 11 e^{x}

Schritte zur Lösung

y^{'} (x) = 5 x + y

Solve linear ODE:

y = - 5 (x + 1) + 11 e^{x}

y = - 5 (x + 1) + 11 e^{x}

\int l x d x

d er i v a t i v e x^{l n (3)}

\int \frac{3 x - 18}{( x - 9 ) ( x - 5 ) ^{2}} d x

\frac{d y}{d t} = 3 y + y^{3}

2 y^{^{''}} + 18 y = 5 cos (3 t)