What is (\partial)/(\partial x)(2xyz) ?

The answer to (\partial)/(\partial x)(2xyz) is 2yz

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(\partial)/(\partial x)(2xyz)

\frac{\partial}{\partial x} (2 x yz)

2 yz

Solution steps

\frac{\partial}{\partial x} (2 x yz)

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 yz \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 yz \cdot 1

Simplify

= 2 yz

d er i v a t i v e 4 x + \frac{1}{x}

\int \frac{6 + 6 x}{1 + x ^{2}} d x

d er i v a t i v e - \frac{13}{s ^{5}}

t a y l or ln (1 + x)

\frac{d}{d x} (\frac{1}{a x + b})

What is (\partial)/(\partial x)(2xyz) ?
The answer to (\partial)/(\partial x)(2xyz) is 2yz