What is the solution for y^{''}-9y^'+9y=0 ?

The solution for y^{''}-9y^'+9y=0 is y=c_{1}e^{((9+3sqrt(5))t)/2}+c_{2}e^{((9-3sqrt(5))t)/2}

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y^{''}-9y^'+9y=0

y^{^{''}} - 9 y^{^{'}} + 9 y = 0

y = c_{1} e^{\frac{( 9 + 3 5 ) t}{2}} + c_{2} e^{\frac{( 9 - 3 5 ) t}{2}}

Solution steps

y^{''} (t) - 9 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( 9 + 3 5 ) t}{2}} + c_{2} e^{\frac{( 9 - 3 5 ) t}{2}}

y = c_{1} e^{\frac{( 9 + 3 5 ) t}{2}} + c_{2} e^{\frac{( 9 - 3 5 ) t}{2}}

n = 1 \sum \infty \frac{2}{n + 7}

a re a y = 6 x, y = 2 x^{2}

\frac{d}{d x} (sin^{3} (5 x^{2}))

\int \frac{1}{5 x ^{3}} d x

t an g e n t f (x) = x^{4} - 20 x^{2} + 64, at x = - 2

What is the solution for y^{''}-9y^'+9y=0 ?
The solution for y^{''}-9y^'+9y=0 is y=c_{1}e^{((9+3sqrt(5))t)/2}+c_{2}e^{((9-3sqrt(5))t)/2}