y^'=(xy^3)/(16)

Lösung

y^{^{'}} = \frac{x y ^{3}}{16}

y = - \frac{16}{x ^{2} + c _{1}}, y = - - \frac{16}{x ^{2} + c _{1}}

Schritte zur Lösung

y^{'} (x) = \frac{x y ^{3}}{16}

Solve separable ODE:

y = - \frac{16}{x ^{2} + c _{1}}, y = - - \frac{16}{x ^{2} + c _{1}}

y = - \frac{16}{x ^{2} + c _{1}}, y = - - \frac{16}{x ^{2} + c _{1}}

\int x^{2} (4 - 2 x^{2}) d x

d er i v a t i v e f (x) = x (x^{3} - x)

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\int \frac{4 x - 11}{2 x ^{2} - 11 x + 15} d x

\frac{\partial}{\partial y} (2 x + arctan (y^{2}))