1600y^{''}-9y=0,y(0)=7,y^'(0)=6

Lösung

1600 y^{^{''}} - 9 y = 0, y (0) = 7, y^{^{'}} (0) = 6

y = (7 + \frac{73}{2}) e^{\frac{3 t}{40}} - \frac{73}{2} e^{- \frac{3 t}{40}}

Schritte zur Lösung

1600 y^{''} (t) - 9 y = 0

Solve linear ODE:

y = (7 + \frac{73}{2}) e^{\frac{3 t}{40}} - \frac{73}{2} e^{- \frac{3 t}{40}}

y = (7 + \frac{73}{2}) e^{\frac{3 t}{40}} - \frac{73}{2} e^{- \frac{3 t}{40}}

x \to - 1 lim (x^{2} + 4 x)

\frac{d y}{d t} = 4 y + y^{4}

t an g e n t f (x) = - \frac{4 x}{x ^{2} + 1}, at x = 0

\int r^{2} (\frac{r ^{3}}{15} - 8)^{4} d r

\frac{\partial}{\partial x} (\frac{s ^{2} + 4}{t - 3})