integral of \sqrt[7]{x^6}

Lösung

\int 7 x^{6} d x

\frac{7}{13} x^{\frac{13}{7}} + C

Schritte zur Lösung

\int 7 x^{6} d x

7 x^{6} = x^{\frac{6}{7}},

angenommen

x \geq 0

= \int x^{\frac{6}{7}} d x

Wende die Potenzregel an

= \frac{7}{13} x^{\frac{13}{7}}

Füge eine Konstante zur Lösung hinzu

= \frac{7}{13} x^{\frac{13}{7}} + C

\frac{\partial}{\partial y} (3 x - 2 y^{4})

\int \frac{x ^{2}}{x ^{3} - 2} d x

a re a x = - 2, x = 3, y = x^{2} - 12, y = x - 6

d er i v a t i v e 1 - x^{12}

\frac{\partial ^{2}}{\partial x ^{2}} (\frac{1}{x y})