(\partial)/(\partial x)(8x^6y^7+6x^4y^8)

Lösung

\frac{\partial}{\partial x} (8 x^{6} y^{7} + 6 x^{4} y^{8})

48 y^{7} x^{5} + 24 y^{8} x^{3}

Schritte zur Lösung

\frac{\partial}{\partial x} (8 x^{6} y^{7} + 6 x^{4} y^{8})

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{6} y^{7}) + \frac{\partial}{\partial x} (6 x^{4} y^{8})

\frac{\partial}{\partial x} (8 x^{6} y^{7}) = 48 y^{7} x^{5}

\frac{\partial}{\partial x} (6 x^{4} y^{8}) = 24 y^{8} x^{3}

= 48 y^{7} x^{5} + 24 y^{8} x^{3}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x + 1})

\int e^{2 x} (cos (3 x)) d x

\int \frac{6}{cos ( x ) - 1} d x

2 y^{^{''}} + 3 y^{^{'}} - 2 y = cos (2 x)

d er i v a t i v e \frac{x}{x ^{2}}