integral of (\sqrt[3]{x}+1/(sqrt(x)))

Lösung

\int (3 x + \frac{1}{x}) d x

\frac{3}{4} x^{\frac{4}{3}} + 2 x + C

Schritte zur Lösung

\int 3 x + \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x + \int \frac{1}{x} d x

\int 3 x d x = \frac{3}{4} x^{\frac{4}{3}}

\int \frac{1}{x} d x = 2 x

= \frac{3}{4} x^{\frac{4}{3}} + 2 x

Füge eine Konstante zur Lösung hinzu

= \frac{3}{4} x^{\frac{4}{3}} + 2 x + C

t an g e n t f (x) = \frac{x}{1 + x ^{2}}, (2, 0.4)

\frac{d}{d x} ((1 - sin (x))^{- \frac{1}{2}})

\int \frac{361}{x ^{3} - 19 x ^{2}} d x

\frac{d}{d x} (\frac{1}{20} e^{x} + x^{6} - x^{e} + e)

\frac{\partial}{\partial x} (sin^{9} (x))