integral from-1 to 2 of sqrt(5x+6)

Lösung

\int_{- 1}^{2} 5 x + 6 d x

\frac{42}{5}

Dezimale

8.4

Schritte zur Lösung

\int_{- 1}^{2} 5 x + 6 d x

Wende U-Substitution an

= \int_{1}^{16} \frac{u}{5} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int_{1}^{16} u d u

Wende die Potenzregel an

= \frac{1}{5} [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{16}

Berechne die Grenzen:

42

= \frac{1}{5} \cdot 42

Vereinfache

= \frac{42}{5}

n = 1 \sum \infty (- 2)^{n} (x)^{n}

y^{^{''}} + 8 y^{^{'}} - 20 y = 0

\frac{d}{d x} (3 (x - 3)^{3} (x + 5))

\frac{\partial}{\partial y} (sin (x - y) + (x + y))

\frac{d y}{d x} = 6 y e^{x + 4}